![]() ![]() This is something you'd want to repeat and it would make it easy to test multiple cases. This is fine as far as I can tell (with h.j.k.'s suggestions of course), I might consider changing last to j or i to first or something so it's consistently named.Your evaluation process should be its own method. ![]() So long as you use & instead of & java will use short circuit evaluation and not do isPalindrome(data).īut! An even better way is to do if (j - i > palindrome.length()) before you even make the substring and see if it's a palindrome. I have also tried using the top and iterate using this variable. Using ArrayUtils.reverse from Apache commons: int arrCopy pyOf (array, array.length) ArrayUtils.reverse (arrCopy) boolean isPalindrome Arrays. Explanation: Input the number you want to check and store it in a temporary (temp) variable. We can check if the given string is a palindrome by comparing the original string with its reversed version. Naive Approach to Check Palindrome String in Java By Reversing the given string and Comparing. First, we turn the string to an array of. You could check if the array is palindrome by comparing it with reversed copy of the original array. There are three major methods to check string palindrome in Java as mentioned below: Naive Method Two Pointer Method Recursive Method 1. Push all the elements till mid into the stack i.e. Examples: Input: str geeksforgeeks Output: No Input: str madam Output: Yes Approach: Find the length of the string say len. ![]() But, due to some reason while popping the stack the program is not working as expected. The example uses the Java Stack container to build a reversed string. Practice Given string str, the task is to find whether the given string is a palindrome or not using a stack. public class LargestPalindrome )Ĭhecking is something is a palindrome with isPalindrome is \$O(n/2)\$ which isn't terrible, but we're only saving it if it's longer than the current one we have, and we can know if it's going to be longer before we know if it's a palindrome by putting data.length() > palindrome.length() before isPalindrome(data). Palindrome using stack Ask Question Asked 7 years, 10 months ago Modified 7 years, 10 months ago Viewed 1k times 1 I wrote a palindrome using stacks in java. ![]() recursive method that checks if a string is palindrome in java. I am working on a question in which I need to find a largest palindrome given a string. Stack Overflow for Teams Where developers & technologists share private knowledge with coworkers Talent Build your employer brand Advertising Reach developers & technologists worldwide. ![]()
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